Given $P(0 < Z < 0.6) = 0.2257$ and $P(0 < Z < 1.8) = 0.4641$ , what is $P(-0.6 < Z < 1.8)$ ?

0.2384

Correct answerYour answer

0.4641

Correct answerYour answer

0.6898

Correct answerYour answer

0.9641

Correct answerYour answer

Show the answer and explanation

CorrectNot quiteAnswer C

Correct answer: C

The interval straddles 0: the part from $-0.6$ to 0 equals the part from 0 to 0.6, 0.2257.
$0.2257 + 0.4641 = 0.6898$ .

Worth noting

0.2384 subtracts the areas, which is for two z-values on the same side of 0.

Ten questions from Normal Distribution, at your own pace.

Ten questions from Normal Distribution, at your own pace.

Given P(0<Z<0.6)=0.2257P(0 < Z < 0.6) = 0.2257P(0<Z<0.6)=0.2257 and P(0<Z<1.8)=0.4641P(0 < Z < 1.8) = 0.4641P(0<Z<1.8)=0.4641, what is P(−0.6<Z<1.8)P(-0.6 < Z < 1.8)P(−0.6<Z<1.8)?