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Normal Distribution · Question 49 of 68

What percentage of the sugar packets weigh less than 490 g?

Question 49

EasyOriginal question

A machine fills packets of sugar. The weights are normally distributed with mean 500 g and standard deviation 5 g. (Take P(0<Z<1)=0.3413P(0 < Z < 1) = 0.3413, P(0<Z<2)=0.4772P(0 < Z < 2) = 0.4772 and P(0<Z<2.5)=0.4938P(0 < Z < 2.5) = 0.4938.)

What percentage of the sugar packets weigh less than 490 g?

Options for question 49

Show the answer and explanation
CorrectNot quiteAnswer A

Correct answer: A

Explanation

  1. z=490−5005=−2z = \frac{490 - 500}{5} = -2.

  2. 0.5−0.4772=0.02280.5 - 0.4772 = 0.0228, so 2.28%.

Worth noting

4.56% counts both tails, light and heavy.

Concept
A lower tail
Typical time
90 s
Your time
—
The rule this testsUsing the normal distribution
Practise this chapter →

Ten questions from Normal Distribution, at your own pace.

Practise this chapter →

Ten questions from Normal Distribution, at your own pace.