Solve (x + 1)/(x - 4) ≤ 0.

Numerical Inequalities · Question 58 of 79

Question 58

HardOriginal question

Solve $\frac{x + 1}{x - 4} \le 0$ .

-1 \le x \le 4

Correct answerYour answer

-1 \le x < 4

Correct answerYour answer

x \le -1

x > 4

Correct answerYour answer

-4 < x \le 1

Correct answerYour answer

Show the answer and explanation

CorrectNot quiteAnswer B

Correct answer: B

The fraction is 0 at $x = -1$ and undefined at $x = 4$ ; between them the top is positive and the bottom negative.
So $-1 \le x < 4$ : $-1$ is included, 4 is not.

Worth noting

$x = 4$ makes the denominator 0, so it can never be included.

Ten questions from Numerical Inequalities, at your own pace.

Ten questions from Numerical Inequalities, at your own pace.