$x < y < 0$. Which of these is true?

Explanation

1. 01

   Both are negative and $x$ is further from 0, so $x^{2} > y^{2}$: for example $-3 < -2$ and $9 > 4$.

2. 02

   Also $\frac{1}{-3} > \frac{1}{-2}$, and the product of two negatives is positive.