Arrange 0.7, (0.7)^2 and √(0.7) in increasing order.

Numerical Inequalities · Question 28 of 79

Question 28

MediumOriginal question

Arrange $0.7$ , $(0.7)^{2}$ and $\sqrt{0.7}$ in increasing order.

\sqrt{0.7} < 0.7 < (0.7)^{2}

Correct answerYour answer

0.7 < (0.7)^{2} < \sqrt{0.7}

Correct answerYour answer

(0.7)^{2} < 0.7 < \sqrt{0.7}

Correct answerYour answer

(0.7)^{2} < \sqrt{0.7} < 0.7

Correct answerYour answer

Show the answer and explanation

CorrectNot quiteAnswer C

Correct answer: C

For a number between 0 and 1, squaring makes it smaller and taking the square root makes it larger.
$(0.7)^{2} = 0.49$ , and $\sqrt{0.7} \approx 0.84$ .

Worth noting

The reverse order is right for numbers above 1, such as 7.

Ten questions from Numerical Inequalities, at your own pace.

Ten questions from Numerical Inequalities, at your own pace.