How do $\frac{1}{\sqrt{3} - \sqrt{2}}$ and $\sqrt{3} + \sqrt{2}$ compare?

Explanation

1. 01

   Multiply top and bottom by $\sqrt{3} + \sqrt{2}$: the bottom becomes $3 - 2 = 1$.

2. 02

   So $\frac{1}{\sqrt{3} - \sqrt{2}} = \sqrt{3} + \sqrt{2}$.