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Perpetuity, Sinking Funds & Bonds · Question 27 of 63

Question 27

MediumOriginal question

₹10,000 is put into a sinking fund at the end of every year for 3 years, at 5% a year. How much is in the fund after the third deposit? (Take (1.05)3=1.157625(1.05)^{3} = 1.157625.)

Options for question 27

Show the answer and explanation
CorrectNot quiteAnswer C

Correct answer: C

Explanation

  1. A=R×(1+i)n−1i=10,000×0.1576250.05A = R \times \frac{(1 + i)^{n} - 1}{i} = 10{,}000 \times \frac{0.157625}{0.05}.

  2. =10,000×3.1525=31,525= 10{,}000 \times 3.1525 = 31{,}525 rupees.

Worth noting

₹30,000 counts the deposits but not the interest they earn.

Concept
What a sinking fund builds up to
Typical time
90 s
Your time
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The rule this testsSinking funds
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Ten questions from Perpetuity, Sinking Funds & Bonds, at your own pace.

Practise this chapter →

Ten questions from Perpetuity, Sinking Funds & Bonds, at your own pace.