Perpetuity, Sinking Funds and Bonds for CUET Applied Maths
About 5 min to learn · 63 questions
Perpetuities, sinking funds and bonds are part of Section B2 of CUET Maths, the Applied Mathematics section you answer if you choose Applied Mathematics instead of Section B1. All three rest on one idea, the present value of money paid later, and CUET prints every power you need, so no calculator is missed. Learn each idea here, from the value of a perpetuity to sinking fund deposits, how a sinking fund differs from a savings account, bond terms and valuing a bond, with worked examples, time-saving shortcuts and the traps CUET sets, then practise on free questions in CUET's own formats, each fully solved.
A school's old students want to fund a ₹12,000 scholarship every year, for ever. How much must they give today? The answer is surprisingly finite, and finding it introduces the idea behind this whole chapter: money due later is worth less today.
A perpetuity is a series of equal payments that goes on for ever. If it pays R at the end of each period and money earns i a period, its present value is PV=iR: the sum whose interest alone pays R every period without ever touching the sum itself.
Example 1 · A scholarship for ever
How much must be invested at 6% a year to pay a scholarship of ₹12,000 at the end of every year for ever?
PV=iR=0.0612,000.
=2,00,000 rupees; its interest each year is exactly ₹12,000.
Answer
₹2,00,000.
Watch out
Use the rate for the payment period. A quarterly payment needs the quarterly rate, a quarter of the yearly rate when interest is compounded quarterly.
A sinking fund is money set aside in equal deposits at regular intervals, earning interest, to meet a known expense on a known future date, such as replacing a machine. If deposits of R are made at the end of each period for n periods at rate i, the fund grows to A=R×i(1+i)n−1, so the deposit needed is R=(1+i)n−1Ai.
Example 2 · Saving for a new machine
A firm needs ₹2,00,000 in 4 years and saves in equal deposits at the end of each year at 10%. Taking (1.1)4=1.4641, what is each deposit?
R=1.4641−12,00,000×0.1=0.464120,000.
R≈43,094 rupees.
Answer
About ₹43,094 a year; the interest makes up the rest of the ₹2,00,000.
Unlike a savings account, a sinking fund is kept for its purpose until the date; a savings account can be drawn on at any time for anything.
A bond is a loan to a government or company. Its face value is the amount repaid at maturity; the coupon rate fixes the yearly interest, coupon rate times face value; the maturity date is when it is repaid; and the yield is the return a buyer earns at the price paid. A bond sells at par at its face value, at a premium above it and at a discount below it.
Key idea
Coupons are fixed when the bond is issued. If market rates rise above the coupon rate, buyers pay less for the bond, so its price falls below face value; if rates fall, its price rises.
Add the present values of everything the holder will receive, each coupon and the face value at maturity, discounted at the required rate of return. When the required rate equals the coupon rate, the value is exactly the face value.
Example 3 · A bond at a premium
A ₹1,000 bond pays a 6% coupon yearly and is repaid in 2 years. Buyers require 5%. Taking 1.051=0.9524 and (1.05)21=0.9070, what is it worth?
Year 1 brings ₹60; year 2 brings 60+1,000=1,060.
Value =60×0.9524+1,060×0.9070=57.14+961.42=1,018.56 rupees.
Answer
About ₹1,018.56: a premium, because 6% beats the 5% buyers require.
A perpetuity of ₹1,000 a year will start with its first payment 3 years from now. At 10% a year, what is it worth today, to the nearest rupee? (Take (1.1)21=0.8264.)
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AnswerB · ₹8,264
Two years from now it is an ordinary perpetuity, worth 0.11,000=10,000 at that time.
Discount it back 2 years: 10,000×0.8264=8,264 rupees.
Worth noting
₹7,513 discounts 3 years; the perpetuity formula already values the payments as of one year before the first.
A shop owner wants ₹5,00,000 in 4 years to buy a new delivery van. She puts an equal sum into a fund at the end of each year, earning 8% a year compounded yearly. (Take (1.08)4=1.36049; answers to the nearest rupee.)
How much does the shop owner pay into the van fund over the 4 years?
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AnswerD · ₹4,43,840
Four deposits of ₹1,10,960.
4×1,10,960=4,43,840 rupees.
Worth noting
₹56,160 is the interest the fund earns, not what she pays in.
A shop owner wants ₹5,00,000 in 4 years to buy a new delivery van. She puts an equal sum into a fund at the end of each year, earning 8% a year compounded yearly. (Take (1.08)4=1.36049; answers to the nearest rupee.)
How much of the van fund's ₹5,00,000 is interest?
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AnswerB · ₹56,160
The deposits total ₹4,43,840.
Interest =5,00,000−4,43,840=56,160 rupees.
Worth noting
₹1,60,000 is 8% of ₹5,00,000 for 4 years, as if the whole sum were there from the start.
A firm must replace a machine in 5 years for ₹1,00,000. It puts an equal sum into a sinking fund at the end of every year, earning 10% a year. To the nearest rupee, what is each deposit? (Take (1.1)5=1.61051.)
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AnswerB · ₹16,380
The deposits R must grow to A: R×i(1+i)n−1=A, so R=(1+i)n−1Ai.
R=0.610511,00,000×0.1≈16,380 rupees.
Worth noting
₹20,000 divides the target by 5 and forgets the interest the deposits earn.
₹5,000 is put into a sinking fund at the end of every year for 4 years, at 8% a year. How much is in the fund after the fourth deposit? (Take (1.08)4=1.3605.)
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AnswerC · ₹22,531.25
The fund is the amount of an annuity: A=R×i(1+i)n−1.
A school needs ₹1,50,000 in 3 years for a new bus. It saves equal sums at the end of each year at 10%. To the nearest rupee, what is each deposit? (Take (1.1)3=1.331.)
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AnswerA · ₹45,317
R=(1+i)n−1Ai=0.3311,50,000×0.1.
R≈45,317 rupees.
Worth noting
₹50,000 divides the target by 3, ignoring the interest earned.
₹10,000 is put into a sinking fund at the end of every year for 3 years, at 5% a year. How much is in the fund after the third deposit? (Take (1.05)3=1.157625.)
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AnswerC · ₹31,525
A=R×i(1+i)n−1=10,000×0.050.157625.
=10,000×3.1525=31,525 rupees.
Worth noting
₹30,000 counts the deposits but not the interest they earn.
A shop owner wants ₹5,00,000 in 4 years to buy a new delivery van. She puts an equal sum into a fund at the end of each year, earning 8% a year compounded yearly. (Take (1.08)4=1.36049; answers to the nearest rupee.)
How much must the shop owner put into the van fund each year?
A company puts ₹50,000 into a sinking fund at the end of every half-year for 3 years, at 8% a year compounded half-yearly. What is the fund worth at the end? (Take (1.04)6=1.2653.)
₹3,000 is put into a fund at the end of every quarter for 2 years, at 8% a year compounded quarterly. To the nearest rupee, how much is in the fund at the end? (Take (1.02)8=1.171659.)
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AnswerC · ₹25,749
Per quarter i=48%=0.02, and there are n=8 deposits.
A=3,000×0.020.171659≈25,749 rupees.
Worth noting
₹6,437 uses the yearly rate, 0.08, with 8 quarterly periods.
A company needs ₹2,00,000 in 2 years. It saves equal sums at the end of every half-year at 12% a year compounded half-yearly. To the nearest rupee, what is each deposit? (Take (1.06)4=1.262477.)
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AnswerA · ₹45,718
Per half-year i=0.06, and n=4 deposits.
R=0.2624772,00,000×0.06≈45,718 rupees.
Worth noting
₹50,000 divides the target by 4 deposits, ignoring interest.
A shop owner wants ₹5,00,000 in 4 years to buy a new delivery van. She puts an equal sum into a fund at the end of each year, earning 8% a year compounded yearly. (Take (1.08)4=1.36049; answers to the nearest rupee.)
How much is in the van fund just after the second deposit?
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AnswerD · ₹2,30,797
The first deposit has earned one year's interest; the second has just gone in.
A bond's face value of ₹1,000 will be repaid in 2 years. Buyers require 6% a year. What is the present value of that repayment alone? (Take (1.06)21=0.8900.)
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AnswerA · ₹890
Discount the repayment back 2 years.
1,000×0.8900=890 rupees.
Worth noting
₹943.40 discounts only one year; ₹1,123.60 grows the sum for two years instead of discounting it.
A bond with face value ₹1,000 pays a 10% coupon and is repaid, with that coupon, in 1 year. Buyers require 8% a year. To the nearest paisa, what is it worth? (Take 1.081=0.9259.)
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AnswerC · ₹1,018.49
In a year the holder receives 1,000+100=1,100 rupees.
Value =1,100×0.9259=1,018.49 rupees, a premium.
Worth noting
₹925.90 discounts the face value but leaves out the coupon.
A zero-coupon bond will pay ₹10,000 in 3 years and nothing before. Buyers require 10% a year. To the nearest paisa, what is it worth today? (Take (1.1)3=1.331.)
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AnswerA · ₹7,513.15
Its only payment is the face value in 3 years.
Value =1.33110,000≈7,513.15 rupees.
Worth noting
₹9,090.91 and ₹8,264.46 discount only one and two years; ₹13,310 grows the sum instead of discounting it.
A bond pays a ₹50 coupon at the end of each of the next 3 years. Buyers require 5% a year. What is the present value of the coupons alone? (Take (1.05)31=0.8638.)
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AnswerC · ₹136.20
The coupons are an annuity: PV =Ri1−(1+i)−n=50×0.051−0.8638.
=50×2.724=136.20 rupees.
Worth noting
₹150 adds the coupons without discounting; ₹129.57 discounts all three by three years.
A bond with face value ₹1,000 pays an 8% coupon yearly and is repaid in 2 years. Buyers require 10% a year. What is the bond worth? (Take 1.11=0.9091 and (1.1)21=0.8264.)
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AnswerB · ₹965.24
Year 1 brings ₹80 and year 2 brings 80+1,000=1,080.
Value =80×0.9091+1,080×0.8264=72.73+892.51=965.24 rupees, below par because 8% is less than 10%.
Worth noting
₹986.40 discounts the face value but adds the ₹160 of coupons at full value.
A bond with face value ₹100 pays a 12% coupon and is repaid, with that coupon, in 1 year. Buyers require 8% a year. To the nearest paisa, what is it worth? (Take 1.081=0.9259.)
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AnswerC · ₹103.70
In a year the holder receives 100+12=112 rupees.
Value =112×0.9259≈103.70 rupees: a premium, as 12% beats 8%.
Worth noting
₹112 is what is received in a year, not what it is worth today.
A ₹1,000 bond pays a 7% coupon yearly and is repaid in 4 years. Buyers require 6%. What is it worth? (Take the present value of ₹1 a year for 4 years at 6% as 3.4651, and (1.06)41=0.7921.)
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AnswerC · ₹1,034.66
Coupons: 70×3.4651=242.557. Face value: 1,000×0.7921=792.10.
Value ≈1,034.66 rupees, a premium, since 7% beats 6%.
Worth noting
₹1,072.10 discounts the coupons but takes the face value undiscounted, at ₹1,000.
A bond with face value ₹1,000 pays a 6% coupon yearly and is repaid in 2 years. Buyers require 8% a year. What is it worth? (Take 1.081=0.9259 and (1.08)21=0.8573.)
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AnswerB · ₹964.29
Year 1: ₹60; year 2: 60+1,000=1,060.
Value =60×0.9259+1,060×0.8573=55.554+908.738=964.292, about ₹964.29, a discount.
Worth noting
₹973.03 discounts the face value but adds the ₹120 of coupons at full value.
NTA's Mathematics / Applied Mathematics syllabus has three sections: Section A1, which every candidate answers, then Section B1 (Mathematics) or Section B2 (Applied Mathematics), of which a candidate answers one. Each section lists units and topics but no chapters, so the chapters here are ours. Where both B sections list a topic that Section A also lists, its questions sit once, in Section A.