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Perpetuity, Sinking Funds & Bonds · Question 31 of 63

Question 31

HardOriginal question

A company needs ₹2,00,000 in 2 years. It saves equal sums at the end of every half-year at 12% a year compounded half-yearly. To the nearest rupee, what is each deposit? (Take (1.06)4=1.262477(1.06)^{4} = 1.262477.)

Options for question 31

Show the answer and explanation
CorrectNot quiteAnswer A

Correct answer: A

Explanation

  1. Per half-year i=0.06i = 0.06, and n=4n = 4 deposits.

  2. R=2,00,000×0.060.262477≈45,718R = \frac{2{,}00{,}000 \times 0.06}{0.262477} \approx 45{,}718 rupees.

Worth noting

₹50,000 divides the target by 4 deposits, ignoring interest.

Concept
A sinking fund with half-yearly deposits
Typical time
120 s
Your time
—
The rule this testsSinking funds
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Ten questions from Perpetuity, Sinking Funds & Bonds, at your own pace.

Practise this chapter →

Ten questions from Perpetuity, Sinking Funds & Bonds, at your own pace.