4 fair coins are tossed. What is the probability of getting at least one head?

\frac{1}{16}

Correct answerYour answer

\frac{1}{4}

Correct answerYour answer

\frac{1}{2}

Correct answerYour answer

\frac{15}{16}

Correct answerYour answer

Show the answer and explanation

CorrectNot quiteAnswer D

Correct answer: D

'At least one head' is the complement of 'no heads', which is $TTTT$ alone: $\frac{1}{16}$ .
$1 - \frac{1}{16} = \frac{15}{16}$ .

Worth noting

$\frac{1}{16}$ is the probability of no heads, the complement.

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