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Random Variables, Expectation & Variance · Question 46 of 68

The fair now charges ₹5 a game to play, with the same prizes.

Question 46

MediumOriginal question

At a fair a player rolls a fair die once. A 6 wins ₹30, a 5 wins ₹12, and any other number loses ₹6. Let XX be the player's winnings in rupees.

The fair now charges ₹5 a game to play, with the same prizes. What does a player expect to lose a game?

Options for question 46

Show the answer and explanation
CorrectNot quiteAnswer A

Correct answer: A

Explanation

  1. Expected winnings before the charge: ₹3.

  2. After paying ₹5: 3−5=−23 - 5 = -2, an expected loss of ₹2.

Worth noting

₹8 adds the charge to the ₹3 instead of taking the ₹3 off it.

Concept
A fixed charge shifts the expectation
Typical time
120 s
Your time
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The rule this testsMathematical expectation
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