Assertion (A): The relation $R = \{(1, 1), (2, 2), (3, 3)\}$ on $\{1, 2, 3\}$ is transitive.
Reason (R): A relation in which every pair has the form $(a, a)$ can only chain a pair with itself.

Both A and R are true, and R is the correct explanation of A.Correct answerYour answerBoth A and R are true, but R is not the correct explanation of A.Correct answerYour answerA is true, but R is false.Correct answerYour answerA is false, but R is true.Correct answerYour answer

Show the answer and explanation

CorrectNot quiteAnswer A

Correct answer: A

A is true: the only chains are $(a, a), (a, a)$ , which need $(a, a)$ , already present.
R is true and is exactly why A holds.

Concept: Transitivity of the identity relation
Typical timeTypical: 120 s
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The rule this testsTypes of relations

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Assertion (A): The relation R={(1,1),(2,2),(3,3)}R = \{(1, 1), (2, 2), (3, 3)\}R={(1,1),(2,2),(3,3)} on {1,2,3}\{1, 2, 3\}{1,2,3} is transitive.Reason (R): A relation in which every pair has the form (a,a)(a, a)(a,a) can only chain a pair with itself.

Explanation

Assertion (A): The relation $R = \{(1, 1), (2, 2), (3, 3)\}$ on $\{1, 2, 3\}$ is transitive.
Reason (R): A relation in which every pair has the form $(a, a)$ can only chain a pair with itself.