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Relations & Functions · Question 103 of 125

Question 103

MediumOriginal question

For which codomain is f(x)=sin⁡xf(x) = \sin x, defined on [−π2,π2]\left[-\frac{\pi}{2}, \frac{\pi}{2}\right], a bijection?

Options for question 103

Show the answer and explanation
CorrectNot quiteAnswer D

Correct answer: D

Explanation

  1. On [−π2,π2]\left[-\frac{\pi}{2}, \frac{\pi}{2}\right], sin⁡x\sin x is strictly increasing, so it is one-one.

  2. It runs from −1-1 to 1, so it is onto exactly when the codomain is [−1,1][-1, 1].

Worth noting

[−π2,π2]\left[-\frac{\pi}{2}, \frac{\pi}{2}\right] is the domain; the codomain has to be the set of values, [−1,1][-1, 1].

Concept
Choosing a codomain to make a bijection
Typical time
90 s
Your time
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The rule this testsOnto and bijective functions
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Ten questions from Relations & Functions, at your own pace.

Practise this chapter →

Ten questions from Relations & Functions, at your own pace.