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Relations & Functions · Question 123 of 125

Question 123

HardOriginal question

Which of these describes f:[−1,1]→[−1,1]f : [-1, 1] \to [-1, 1], f(x)=x∣x∣f(x) = x\lvert x \rvert?

Options for question 123

Show the answer and explanation
CorrectNot quiteAnswer D

Correct answer: D

Explanation

  1. f(x)=−x2f(x) = -x^{2} for x<0x < 0 and x2x^{2} for x≥0x \ge 0: strictly increasing, so one-one.

  2. It runs from f(−1)=−1f(-1) = -1 to f(1)=1f(1) = 1: onto [−1,1][-1, 1].

Worth noting

Unlike x2x^{2}, x∣x∣x\lvert x \rvert keeps the sign of xx, so it never repeats.

Concept
Classifying a function
Typical time
120 s
Your time
—
The rule this testsOnto and bijective functions
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Ten questions from Relations & Functions, at your own pace.

Practise this chapter →

Ten questions from Relations & Functions, at your own pace.