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Three-Dimensional Geometry · Question 36 of 120

What are the coordinates of M?

Question 36

EasyOriginal question

A point P(5,1,4)P(5, 1, 4) and the line L:x−12=y2=z−3−1L: \frac{x - 1}{2} = \frac{y}{2} = \frac{z - 3}{-1} are given. MM is the point of LL with parameter λ\lambda, and FF is the foot of the perpendicular from PP to LL.

What are the coordinates of MM?

Options for question 36

Show the answer and explanation
CorrectNot quiteAnswer A

Correct answer: A

Explanation

  1. Set each fraction equal to λ\lambda: x−1=2λx - 1 = 2\lambda, y=2λy = 2\lambda, z−3=−λz - 3 = -\lambda.

  2. So M=(1+2λ,2λ,3−λ)M = (1 + 2\lambda, 2\lambda, 3 - \lambda).

Worth noting

(2+λ,2,−1+3λ)(2 + \lambda, 2, -1 + 3\lambda) swaps the point (1,0,3)(1, 0, 3) and the direction 2,2,−12, 2, -1.

Concept
The foot of the perpendicular from a point to a line
Typical time
90 s
Your time
—
The rule this testsThe equation of a line
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Ten questions from Three-Dimensional Geometry, at your own pace.

Practise this chapter →

Ten questions from Three-Dimensional Geometry, at your own pace.