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Vectors · Question 45 of 125

Question 45

MediumOriginal question

What are the direction cosines of the vector from A(2,−1,3)A(2, -1, 3) to B(4,1,2)B(4, 1, 2)?

Options for question 45

Show the answer and explanation
CorrectNot quiteAnswer B

Correct answer: B

Explanation

  1. AB→=(4−2)i^+(1+1)j^+(2−3)k^=2i^+2j^−k^\overrightarrow{AB} = (4 - 2)\hat{i} + (1 + 1)\hat{j} + (2 - 3)\hat{k} = 2\hat{i} + 2\hat{j} - \hat{k}, of magnitude 4+4+1=3\sqrt{4 + 4 + 1} = 3.

  2. Divide each component by 3: 23,23,−13\frac{2}{3}, \frac{2}{3}, -\frac{1}{3}.

Worth noting

−23,−23,13-\frac{2}{3}, -\frac{2}{3}, \frac{1}{3} belong to BA→\overrightarrow{BA}: the vector from AA to BB is BB minus AA.

Concept
Direction cosines of the vector joining two points
Typical time
90 s
Your time
—
The rule this testsAddition, components and the section formula
Practise this chapter →

Ten questions from Vectors, at your own pace.

Practise this chapter →

Ten questions from Vectors, at your own pace.