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Vectors · Question 107 of 125

Question 107

MediumOriginal question

Assertion (A): If a⃗×b⃗=0⃗\vec{a} \times \vec{b} = \vec{0} and a⃗⋅b⃗=0\vec{a} \cdot \vec{b} = 0, then a⃗=0⃗\vec{a} = \vec{0} or b⃗=0⃗\vec{b} = \vec{0}.

Reason (R): For non-zero vectors, a⃗×b⃗=0⃗\vec{a} \times \vec{b} = \vec{0} means they are parallel, and a⃗⋅b⃗=0\vec{a} \cdot \vec{b} = 0 means they are perpendicular.

Options for question 107

Show the answer and explanation
CorrectNot quiteAnswer A

Correct answer: A

Explanation

  1. R is true: ∣a⃗∣∣b⃗∣sin⁡θ=0\lvert \vec{a} \rvert \lvert \vec{b} \rvert \sin \theta = 0 forces sin⁡θ=0\sin \theta = 0, and ∣a⃗∣∣b⃗∣cos⁡θ=0\lvert \vec{a} \rvert \lvert \vec{b} \rvert \cos \theta = 0 forces cos⁡θ=0\cos \theta = 0.

  2. No angle has both sine and cosine 0, so two non-zero vectors cannot do both: one of them is 0⃗\vec{0}. A is true, and R explains it.

Concept
When both products vanish
Typical time
90 s
Your time
—
The rule this testsThe vector product
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Ten questions from Vectors, at your own pace.

Practise this chapter →

Ten questions from Vectors, at your own pace.