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Counting and Basic Probability · Question 30 of 65

Question 30

HardOriginal question

A quiz team of 4 is to be picked from 5 boys and 4 girls. The team must include at least 2 girls. How many different teams are possible?

Options for question 30

Show the answer and explanation
CorrectNot quiteAnswer B

Correct answer: B

Explanation

  1. Split into cases by the number of girls.

  2. 2 girls: 4C2×5C2=6×10=60{}^{4}C_{2} \times {}^{5}C_{2} = 6 \times 10 = 60. 3 girls: 4C3×5C1=4×5=20{}^{4}C_{3} \times {}^{5}C_{1} = 4 \times 5 = 20. 4 girls: 4C4=1{}^{4}C_{4} = 1.

  3. Teams =60+20+1=81= 60 + 20 + 1 = 81.

  4. Check: total teams 9C4=126{}^{9}C_{4} = 126, minus 5 with no girl and 40 with one girl, gives 81.

Worth noting

60 is only the 'exactly 2 girls' case. 86 subtracts the one-girl teams but forgets the all-boy teams. 126 ignores the condition.

Concept
'At least' condition in a selection, by cases
Typical time
120 s
Your time
—
The rule this testsArrangements and selections
Practise this chapter →

Ten questions from Counting and Basic Probability, at your own pace.

Practise this chapter →

Ten questions from Counting and Basic Probability, at your own pace.