Question 35
HardOriginal questionAn object 18 cm in front of the concave mirror of focal length 12 cm in the figure forms a real image. How many times as tall as the object is the image?
Show the answer and explanation
CorrectNot quiteAnswer C
Correct answer: C
Explanation
Mirror formula: 1/v + 1/u = 1/f, with u = −18 cm and f = −12 cm.
1/v = −1/12 + 1/18 = −3/36 + 2/36 = −1/36, so v = −36 cm (36 cm in front of the mirror).
Magnification m = −v/u = −(−36)/(−18) = −2: the image is inverted and 2 times as tall.
Worth noting
1.5 is u ÷ f and 0.5 is the reciprocal of the right answer; magnification compares the image distance with the object distance.
- Concept
- Mirror formula and magnification
- Typical timeTypical
- 90 s
- Your timeYours
- —
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