A dairy has three tanks holding 403 L, 434 L and 465 L of milk. What is the capacity of the largest can that can measure the milk of each tank exactly, in whole fills?

Explanation

1. 01

   The can must divide all three quantities, so find HCF(403, 434, 465).

2. 02

   $403 = 13 \times 31$, $434 = 14 \times 31$, $465 = 15 \times 31$.

3. 03

   $\operatorname{HCF} = 31$ L.