Three ribbons are 3.6 m, 4.8 m and 7.2 m long. They are cut into pieces of equal length, the longest possible, with no ribbon left over. How many pieces are obtained in all?

Explanation

1. 01

   In cm: 360, 480, 720. Longest piece = HCF(360, 480, 720) = 120 cm.

2. 02

   Pieces = $360 \div 120 + 480 \div 120 + 720 \div 120 = 3 + 4 + 6$.

3. 03

   Total = 13 pieces.