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HCF & LCM · Question 56 of 63

Question 56

MediumOriginal question

In a lucky draw, tickets are numbered 1 to 500. A prize goes to every ticket whose number is divisible by both 6 and 15. How many tickets win a prize?

Options for question 56

Show the answer and explanation
CorrectNot quiteAnswer B

Correct answer: B

Explanation

  1. Divisible by both 6 and 15 means divisible by LCM⁡(6,15)=30\operatorname{LCM}(6, 15) = 30.

  2. Multiples of 30 up to 500: 500÷30=16500 \div 30 = 16 remainder 20.

  3. So 16 tickets win.

Worth noting

5 comes from using 6×15=906 \times 15 = 90 instead of the LCM 30; 83 counts multiples of 6 only.

Concept
Counting common multiples
Typical time
60 s
Your time
—
The rule this testsHCF and LCM word problems
Practise this chapter →

Ten questions from HCF & LCM, at your own pace.

Practise this chapter →

Ten questions from HCF & LCM, at your own pace.