EduFarming
Your list · 0हिं

Type at least two letters. Press Esc to close.

↑↓ navigate↵ openTAB cycle filter

Number System · Question 31 of 71

Question 31

MediumOriginal question

The five-digit number 6☐432 is divisible by 11. What digit goes in the box?

Options for question 31

Show the answer and explanation
CorrectNot quiteAnswer D

Correct answer: D

Explanation

  1. Digits in odd places (1st, 3rd, 5th): 6+4+2=126 + 4 + 2 = 12. Digits in even places: □+3\square + 3.

  2. The difference 12−(□+3)=9−□12 - (\square + 3) = 9 - \square must be 0 or a multiple of 11.

  3. So □=9\square = 9, giving 69,432=11×6,31269{,}432 = 11 \times 6{,}312.

Worth noting

Keep the digits in their own alternate groups; mixing up positions gives the wrong equation.

Concept
Missing digit for divisibility by 11
Typical time
60 s
Your time
—
The rule this testsDivisibility rules
Practise this chapter →

Ten questions from Number System, at your own pace.

Practise this chapter →

Ten questions from Number System, at your own pace.