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Number System · Question 67 of 71

Question 67

MediumOriginal question

Lalremsiami buys square tiles in boxes of 2,880 each. What is the least number of boxes she must use so that all the tiles, with none left over, can be laid out as one complete square?

Options for question 67

Show the answer and explanation
CorrectNot quiteAnswer C

Correct answer: C

Explanation

  1. 2,880=26×32×52{,}880 = 2^6 \times 3^2 \times 5.

  2. The powers of 2 and 3 are even; only 5 has an odd power.

  3. So she needs 5 boxes: 2,880×5=14,400=12022{,}880 \times 5 = 14{,}400 = 120^2 tiles.

Worth noting

10 boxes fail: 28,800=228{,}800 = 2⁷ × 32×523^2 \times 5^2 has an odd power of 2. Only the prime with an odd power needs fixing.

Concept
Smallest multiplier for a perfect square in context
Typical time
60 s
Your time
—
The rule this testsFactors and prime numbers
Practise this chapter →

Ten questions from Number System, at your own pace.

Practise this chapter →

Ten questions from Number System, at your own pace.