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Percentages · Question 10 of 72

Question 10

MediumOriginal question

In a college election with only two candidates, the winner got 58% of the valid votes and won by 4,800 votes. How many valid votes were cast?

Options for question 10

Show the answer and explanation
CorrectNot quiteAnswer C

Correct answer: C

Explanation

  1. Loser's share = 100%−58%=42%100\% - 58\% = 42\%.

  2. Winning margin = 58%−42%=16%58\% - 42\% = 16\% of the valid votes.

  3. 16% of valid votes = 4,800, so valid votes = 480016×100=30,000\frac{4800}{16} \times 100 = 30{,}000.

Worth noting

The margin is the gap between the two shares (16%), not 58%−50%=8%58\% - 50\% = 8\%, which gives 60,000.

Concept
Using the percentage margin between two candidates
Typical time
70 s
Your time
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The rule this testsPercentage basics
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Ten questions from Percentages, at your own pace.

Practise this chapter →

Ten questions from Percentages, at your own pace.