Evaluate $(5^0 + 4^{-1}) \times 8$.

Explanation

1. 01

   Any non-zero number to the power 0 is 1, so $5^0 = 1$.

2. 02

   A negative power is a reciprocal: $4^{-1} = \frac{1}{4}$.

3. 03

   $\left(1 + \frac{1}{4}\right) \times 8 = \frac{5}{4} \times 8 = 10$.