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Time, Speed & Distance · Question 20 of 71

Question 20

HardOriginal question

If Joseph drives to a wedding at 50 km/h he arrives 12 minutes late; at 60 km/h he arrives 8 minutes early. How far is the wedding venue?

Options for question 20

Show the answer and explanation
CorrectNot quiteAnswer C

Correct answer: C

Explanation

  1. The times differ by 12+8=2012 + 8 = 20 min =13= \frac{1}{3} h.

  2. d50−d60=d300=13\frac{d}{50} - \frac{d}{60} = \frac{d}{300} = \frac{1}{3}.

  3. d=100d = 100 km.

Worth noting

Using 12−8=412 - 8 = 4 minutes gives 20 km. Late and early lie on opposite sides of the scheduled time, so the minutes add.

Concept
Late-and-early problems solved with the difference of times
Typical time
90 s
Your time
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The rule this testsSpeed, conversion and average speed
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