A car is stolen at 2:00 p.m. and driven away at 60 km/h. The owner discovers the theft at 2:30 p.m. and sets off after it from that spot, along the same highway, at 75 km/h. How far from the spot of the theft is the car caught?

Explanation

1. 01

   By 2:30 p.m. the thief is $60 \times \frac{1}{2} = 30$ km ahead.

2. 02

   The owner gains at $75 - 60 = 15$ km/h, so he needs $\frac{30}{15} = 2$ h.

3. 03

   In 2 h the owner covers $75 \times 2 = 150$ km (the thief: $30 + 120 = 150$ km, the same point).