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Area of Bounded Regions · Question 99 of 115

Question 99

MediumOriginal question

Which integral gives the area enclosed by the ellipse x2a2+y2b2=1\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1?

Options for question 99

Show the answer and explanation
CorrectNot quiteAnswer D

Correct answer: D

Explanation

  1. Solving for yy in the first quadrant: y=baa2−x2y = \frac{b}{a}\sqrt{a^{2} - x^{2}}, for 0≤x≤a0 \le x \le a.

  2. Four equal quadrants give 4ba∫0aa2−x2 dx=πab\frac{4b}{a}\int_0^{a} \sqrt{a^{2} - x^{2}}\,dx = \pi ab.

Worth noting

4ab\frac{4a}{b} solves for yy with the semi-axes swapped.

Concept
Setting up the area integral
Typical time
90 s
Your time
—
The rule this testsEllipses
Practise this chapter →

Ten questions from Area of Bounded Regions, at your own pace.

Practise this chapter →

Ten questions from Area of Bounded Regions, at your own pace.