$P(A) = \frac{7}{13}$, $P(B) = \frac{9}{13}$ and $P(A \cap B) = \frac{4}{13}$. What is $P(B \mid A)$?

Explanation

1. 01

   $P(A \mid B) = \frac{P(A \cap B)}{P(B)}$, and $P(A' \mid B) = 1 - P(A \mid B)$.

2. 02

   $P(B \mid A) = \frac{\frac{4}{13}}{\frac{7}{13}} = \frac{4}{7}$.