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Conditional Probability & Bayes' Theorem · Question 4 of 125

What is P(E)?

Question 4

EasyOriginal question

Two fair dice are thrown. EE: the sum is 9. FF: at least one die shows a 5.

What is P(E)P(E)?

Options for question 4

Show the answer and explanation
CorrectNot quiteAnswer B

Correct answer: B

Explanation

  1. Sum 9: (3,6),(4,5),(5,4),(6,3)(3, 6), (4, 5), (5, 4), (6, 3).

  2. 436=19\frac{4}{36} = \frac{1}{9}.

Worth noting

112\frac{1}{12} counts (4,5)(4, 5) and (5,4)(5, 4) as one outcome, and (3,6)(3, 6), (6,3)(6, 3) as one.

Concept
Counting outcomes of two dice
Typical time
90 s
Your time
—
The rule this testsConditional probability
Practise this chapter →

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.

Practise this chapter →

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.