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Conditional Probability & Bayes' Theorem · Question 32 of 125

Question 32

EasyOriginal question

A box has 6 white and 4 black marbles. Two are drawn one after the other without replacement. What is the probability that both are white?

Options for question 32

Show the answer and explanation
CorrectNot quiteAnswer A

Correct answer: A

Explanation

  1. First white: 610\frac{6}{10}; then 5 white of 9 left: 59\frac{5}{9}.

  2. 610×59=13\frac{6}{10} \times \frac{5}{9} = \frac{1}{3}.

Worth noting

925=(35)2\frac{9}{25} = \left(\frac{3}{5}\right)^{2} puts the first marble back.

Concept
Probabilities without replacement
Typical time
60 s
Your time
—
The rule this testsThe multiplication theorem
Practise this chapter →

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.

Practise this chapter →

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.