Two cards are drawn one after the other, without replacement, from a pack of 52. What is the probability that the first is a king and the second a queen?

Explanation

1. 01

   $P(K_1) = \frac{4}{52}$; all 4 queens are still among the 51 cards left: $P(Q_2 \mid K_1) = \frac{4}{51}$.

2. 02

   $\frac{4}{52} \times \frac{4}{51} = \frac{4}{663}$.