Three cards are drawn one after the other, without replacement, from a pack of 52. What is the probability that all three are aces?

Explanation

1. 01

   $\frac{4}{52} \times \frac{3}{51} \times \frac{2}{50}$, each draw leaving one ace and one card fewer.

2. 02

   $= \frac{24}{132600} = \frac{1}{5525}$.