$A$ and $B$ are independent with $P(A) = 0.4$ and $P(B) = 0.7$ . What is $P(A' \cup B')$ ?

0.18

Correct answerYour answer

0.28

Correct answerYour answer

0.72

Correct answerYour answer

0.82

Correct answerYour answer

Show the answer and explanation

CorrectNot quiteAnswer C

Correct answer: C

Worth noting

0.18 is $P(A' \cap B') = 0.6 \times 0.3$ , neither happening; $A' \cup B'$ means at most one happens.

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.

AAA and BBB are independent with P(A)=0.4P(A) = 0.4P(A)=0.4 and P(B)=0.7P(B) = 0.7P(B)=0.7. What is P(A′∪B′)P(A' \cup B')P(A′∪B′)?