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Conditional Probability & Bayes' Theorem · Question 87 of 125

Question 87

MediumOriginal question

P(A)=0.5P(A) = 0.5, P(B∣A)=0.4P(B \mid A) = 0.4 and P(B∣A′)=0.2P(B \mid A') = 0.2. What is P(B)P(B)?

Options for question 87

Show the answer and explanation
CorrectNot quiteAnswer A

Correct answer: A

Explanation

  1. AA and A′A' split the sample space: P(B)=P(A)P(B∣A)+P(A′)P(B∣A′)P(B) = P(A)P(B \mid A) + P(A')P(B \mid A').

  2. 0.5×0.4+0.5×0.2=0.30.5 \times 0.4 + 0.5 \times 0.2 = 0.3.

Worth noting

0.6 adds the two conditional probabilities without weighting them by P(A)P(A) and P(A′)P(A').

Concept
The theorem of total probability
Typical time
90 s
Your time
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The rule this testsThe theorem of total probability
Practise this chapter →

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.

Practise this chapter →

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.