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Conditional Probability & Bayes' Theorem · Question 40 of 125

Question 40

MediumOriginal question

A candidate clears the first round of a selection with probability 0.8. Having cleared it, the candidate clears the second round with probability 0.6, and having cleared both, the third round with probability 0.75. What is the probability that the candidate clears the first two rounds but not the third?

Options for question 40

Show the answer and explanation
CorrectNot quiteAnswer A

Correct answer: A

Explanation

  1. Once the first two rounds are cleared, the third is missed with probability 1−0.75=0.251 - 0.75 = 0.25.

  2. 0.8×0.6×0.25=0.120.8 \times 0.6 \times 0.25 = 0.12.

Worth noting

0.25 is the chance of missing the third round once the first two are cleared; the candidate must first clear them, with probability 0.8×0.60.8 \times 0.6.

Concept
The multiplication theorem for three draws or stages
Typical time
90 s
Your time
—
The rule this testsThe multiplication theorem
Practise this chapter →

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.

Practise this chapter →

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.