EduFarming
Your list · 0हिं

Type at least two letters. Press Esc to close.

↑↓ navigate↵ openTAB cycle filter

Conditional Probability & Bayes' Theorem · Question 61 of 125

Question 61

MediumOriginal question

Three shooters hit a target independently with probabilities 45\frac{4}{5}, 56\frac{5}{6} and 12\frac{1}{2}. What is the probability that all three hit it?

Options for question 61

Show the answer and explanation
CorrectNot quiteAnswer B

Correct answer: B

Explanation

  1. For independent events, multiply.

  2. 45×56×12=13\frac{4}{5} \times \frac{5}{6} \times \frac{1}{2} = \frac{1}{3}.

Worth noting

160\frac{1}{60} is the chance that all three miss.

Concept
Probabilities with independent events
Typical time
90 s
Your time
—
The rule this testsIndependent events
Practise this chapter →

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.

Practise this chapter →

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.