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Conditional Probability & Bayes' Theorem · Question 75 of 125

Question 75

HardOriginal question

In a quiz, three contestants answer the same question independently; the probabilities that they answer it correctly are 45\frac{4}{5}, 12\frac{1}{2} and 14\frac{1}{4}. What is the probability that exactly one of them answers it correctly?

Options for question 75

Show the answer and explanation
CorrectNot quiteAnswer C

Correct answer: C

Explanation

  1. Only the first: 45×12×34=1240\frac{4}{5} \times \frac{1}{2} \times \frac{3}{4} = \frac{12}{40}; only the second: 15×12×34=340\frac{1}{5} \times \frac{1}{2} \times \frac{3}{4} = \frac{3}{40}; only the third: 15×12×14=140\frac{1}{5} \times \frac{1}{2} \times \frac{1}{4} = \frac{1}{40}.

  2. 12+3+140=1640=25\frac{12 + 3 + 1}{40} = \frac{16}{40} = \frac{2}{5}.

Worth noting

3740=1−15×12×34\frac{37}{40} = 1 - \frac{1}{5} \times \frac{1}{2} \times \frac{3}{4} is at least one correct answer, which also counts two or three.

Concept
Two or three independent trials
Typical time
120 s
Your time
—
The rule this testsIndependent events
Practise this chapter →

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.

Practise this chapter →

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.