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Conditional Probability & Bayes' Theorem · Question 41 of 125

Question 41

MediumOriginal question

A basket has 10 mangoes, of which 3 are spoilt. Three mangoes are taken out one after the other without replacement. What is the probability that at least one of them is spoilt?

Options for question 41

Show the answer and explanation
CorrectNot quiteAnswer D

Correct answer: D

Explanation

  1. None spoilt: 710×69×58=724\frac{7}{10} \times \frac{6}{9} \times \frac{5}{8} = \frac{7}{24}.

  2. At least one spoilt: 1−724=17241 - \frac{7}{24} = \frac{17}{24}.

Worth noting

6571000=1−(710)3\frac{657}{1000} = 1 - \left(\frac{7}{10}\right)^{3} puts each mango back before the next one is taken.

Concept
At least one, through the complement of a chain of draws
Typical time
90 s
Your time
—
The rule this testsThe multiplication theorem
Practise this chapter →

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.

Practise this chapter →

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.