A bag has 3 red, 2 blue and 5 green beads. Three are drawn one after the other without replacement. What is the probability of red, then blue, then green, in that order?

Explanation

1. 01

   $\frac{3}{10}$ for red, then $\frac{2}{9}$ for blue, then $\frac{5}{8}$ for green.

2. 02

   $\frac{3 \times 2 \times 5}{10 \times 9 \times 8} = \frac{30}{720} = \frac{1}{24}$.