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Conditional Probability & Bayes' Theorem · Question 53 of 125

Question 53

EasyOriginal question

A problem is given to two students, who solve it independently with probabilities 12\frac{1}{2} and 13\frac{1}{3}. What is the probability that the problem is solved?

Options for question 53

Show the answer and explanation
CorrectNot quiteAnswer C

Correct answer: C

Explanation

  1. The problem stays unsolved only if both fail: 12×23=13\frac{1}{2} \times \frac{2}{3} = \frac{1}{3}.

  2. 1−13=231 - \frac{1}{3} = \frac{2}{3}.

Worth noting

56\frac{5}{6} adds the two chances, counting twice the case where both solve it.

Concept
Probabilities with independent events
Typical time
60 s
Your time
—
The rule this testsIndependent events
Practise this chapter →

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.

Practise this chapter →

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.