For f(x) = x^2 + 1 if x < 3; 5x - 4 if x ≥ 3, what is the left-hand limit at x = 3?

Continuity & Differentiability · Question 4 of 125

Question 4

EasyOriginal question

For $f(x) = \begin{cases} x^{2} + 1, & x < 3 \\ 5x - 4, & x \ge 3 \end{cases}$ , what is the left-hand limit at $x = 3$ ?

9

Correct answerYour answer

10

Correct answerYour answer

11

Correct answerYour answer

15

Correct answerYour answer

Show the answer and explanation

CorrectNot quiteAnswer B

Correct answer: B

Worth noting

11 is the right-hand piece at 3.

Ten questions from Continuity & Differentiability, at your own pace.

Ten questions from Continuity & Differentiability, at your own pace.