f(x) = (x^2 - 16)/(x - 4) for x ≠ 4, and f(4) = k. For which k is f continuous at x = 4?

Continuity & Differentiability · Question 32 of 125

Question 32

EasyOriginal question

$f(x) = \frac{x^{2} - 16}{x - 4}$ for $x \ne 4$ , and $f(4) = k$ . For which $k$ is $f$ continuous at $x = 4$ ?

0

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4

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8

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16

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CorrectNot quiteAnswer C

Correct answer: C

Worth noting

4 takes only the $x$ of $x + 4$ .

Ten questions from Continuity & Differentiability, at your own pace.

Ten questions from Continuity & Differentiability, at your own pace.