f(x) = (x^3 - 27)/(x - 3) for x ≠ 3, and f(3) = k. For which k is f continuous at x = 3?

Continuity & Differentiability · Question 33 of 125

Question 33

EasyOriginal question

$f(x) = \frac{x^{3} - 27}{x - 3}$ for $x \ne 3$ , and $f(3) = k$ . For which $k$ is $f$ continuous at $x = 3$ ?

0

Correct answerYour answer

3

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9

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27

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Show the answer and explanation

CorrectNot quiteAnswer D

Correct answer: D

Worth noting

9 keeps only the $x^{2}$ term of $x^{2} + 3x + 9$ .

Ten questions from Continuity & Differentiability, at your own pace.

Ten questions from Continuity & Differentiability, at your own pace.