For which value of k is f(x) = kx - 1 if x < 2; k + 3 if x ≥ 2 continuous at x = 2?

Continuity & Differentiability · Question 34 of 125

Question 34

EasyOriginal question

For which value of $k$ is $f(x) = \begin{cases} kx - 1, & x < 2 \\ k + 3, & x \ge 2 \end{cases}$ continuous at $x = 2$ ?

1

Correct answerYour answer

\frac{4}{3}

Correct answerYour answer

2

Correct answerYour answer

4

Correct answerYour answer

Show the answer and explanation

CorrectNot quiteAnswer D

Correct answer: D

Worth noting

2 forgets the $k$ in the right-hand piece and solves $2k - 1 = 3$ .

Ten questions from Continuity & Differentiability, at your own pace.

Ten questions from Continuity & Differentiability, at your own pace.