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Continuity & Differentiability · Question 98 of 125

Question 98

MediumOriginal question

What are the left-hand and right-hand derivatives of f(x)=∣x−1∣+xf(x) = \lvert x - 1 \rvert + x at x=1x = 1?

Options for question 98

Show the answer and explanation
CorrectNot quiteAnswer C

Correct answer: C

Explanation

  1. Left of 1: f=1−x+x=1f = 1 - x + x = 1, slope 0.

  2. Right of 1: f=x−1+x=2x−1f = x - 1 + x = 2x - 1, slope 2.

Worth noting

−1-1 and 1 are the slopes of ∣x−1∣\lvert x - 1 \rvert alone; the +x+x adds 1 to each.

Concept
One-sided derivatives
Typical time
90 s
Your time
—
The rule this testsDifferentiability
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Ten questions from Continuity & Differentiability, at your own pace.

Practise this chapter →

Ten questions from Continuity & Differentiability, at your own pace.