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Continuity & Differentiability · Question 109 of 125

Question 109

MediumOriginal question

At how many points in the open interval (0,3)(0, 3) is f(x)=[x]+∣x−2∣f(x) = [x] + \lvert x - 2 \rvert not differentiable?

Options for question 109

Show the answer and explanation
CorrectNot quiteAnswer C

Correct answer: C

Explanation

  1. [x][x] jumps at 1 and 2, so ff is not even continuous there, and hence not differentiable.

  2. ∣x−2∣\lvert x - 2 \rvert has its corner at 2, a point already counted. So 2 points.

Worth noting

3 counts x=2x = 2 twice, once for the jump and once for the corner; it is one point.

Concept
Counting points where a function is not differentiable
Typical time
90 s
Your time
—
The rule this testsDifferentiability
Practise this chapter →

Ten questions from Continuity & Differentiability, at your own pace.

Practise this chapter →

Ten questions from Continuity & Differentiability, at your own pace.