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Derivatives & Second-Order Derivatives · Question 51 of 96

Question 51

MediumOriginal question

Read the two statements and choose the correct option.

I. If x=f(t)x = f(t) and y=g(t)y = g(t), then dydx=dy/dtdx/dt\frac{dy}{dx} = \frac{dy/dt}{dx/dt} wherever dxdt≠0\frac{dx}{dt} \ne 0.

II. If x=f(t)x = f(t) and y=g(t)y = g(t), then d2ydx2=d2y/dt2d2x/dt2\frac{d^2y}{dx^2} = \frac{d^2y/dt^2}{d^2x/dt^2}.

Options for question 51

Show the answer and explanation
CorrectNot quiteAnswer A

Correct answer: A

Explanation

  1. I is the chain rule dydt=dydx⋅dxdt\frac{dy}{dt} = \frac{dy}{dx} \cdot \frac{dx}{dt}, divided through. It is true.

  2. II is false. For x=t2x = t^2, y=t3y = t^3: dydx=3t2\frac{dy}{dx} = \frac{3t}{2}, so d2ydx2=3/22t=34t\frac{d^2y}{dx^2} = \frac{3/2}{2t} = \frac{3}{4t}, while the ratio in II is 6t2=3t\frac{6t}{2} = 3t.

Concept
The parametric rule
Typical time
90 s
Your time
—
The rule this testsParametric functions
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Ten questions from Derivatives & Second-Order Derivatives, at your own pace.

Practise this chapter →

Ten questions from Derivatives & Second-Order Derivatives, at your own pace.