For $f(x) = x^{3} - 6 x^{2} + 9 x$ , at what value of $x$ is $f''(x) = 0$ ?

0

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1

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2

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3

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Show the answer and explanation

CorrectNot quiteAnswer C

Correct answer: C

Worth noting

1 and 3 are where $f'(x) = 0$ , the first derivative.

Ten questions from Derivatives & Second-Order Derivatives, at your own pace.

Ten questions from Derivatives & Second-Order Derivatives, at your own pace.

For f(x)=x3−6x2+9xf(x) = x^{3} - 6 x^{2} + 9 xf(x)=x3−6x2+9x, at what value of xxx is f′′(x)=0f''(x) = 0f′′(x)=0?